The MIPS R4000 can perform multiplication and division in hardware, but it does so in an unusual way, and this is where the temperamental HI and LO registers enter the picture.
The HI and LO registers are 32-bit registers which hold or accumulate the results of a multiplication or addition. You cannot operate on them directly. They are set by a suitable arithmetic operation, and by special instructions for moving values in and out.
The multiplication instructions treat HI and LO as a logical 64-bit register, where the high-order 32 bits are in the HI register and the low-order 32 bits are in the LO register.
MUL rd, rs, rt ; rd = rs * rt, corrupts HI and LO MULT rs, rt ; HI:LO = rs * rt (signed) MULTU rs, rt ; HI:LO = rs * rt (unsigned)
The simplest version is
MUL which multiples two
32-bit registers and stores a 32-bit result into a general-purpose register.
As a side effect, it corrupts the HI and LO registers.
(This is the only multiplication or division operation that puts the result
in a general-purpose register instead of into
HI and LO.)
MULT instruction multiplies two signed 32-bit values
to form a 64-bit result,
which it stores in HI and LO.
MULTU instruction does the same thing,
but treats the factors as unsigned.
The next group of multiplication instructions performs accumulation.
MADD rs, rt ; HI:LO += rs * rt (signed) MADDU rs, rt ; HI:LO += rs * rt (unsigned) MSUB rs, rt ; HI:LO -= rs * rt (signed) MSUBU rs, rt ; HI:LO -= rs * rt (unsigned)
After performing the appropriate multiplication operation, the 64-bit result is added to or subtracted from the value currently in the HI and LO registers.
Note that the
U suffix applies to the signed-ness
of the multiplication, not to whether the operation traps on
signed overflow during addition or subtraction.
None of the multiplication instructions trap.
The operation runs faster if you put the smaller factor in rt, so if you know (or suspect) that one of the values is smaller than the other, you can try to arrange for the smaller number to be in rt.
You might think that the division operations take a 64-bit value in HI and LO and divide it by a 32-bit register. But you'd be wrong. They divide a 32-bit value by another 32-bit value and store the quotient and remainder in in HI and LO.
DIV rd, rs, rt ; LO = rs / rt, HI = rs % rt (signed) DIVU rd, rs, rt ; LO = rs / rt, HI = rs % rt (unsigned)
None of the division operations trap, not even for overflow or divide-by-zero. If you divide by zero or incur division overflow, the results in HI and LO are garbage. If you care about overflow or division by zero, you need to check for it explicitly.
Okay, that's great.
We've done some calculations and put the results into
HI and LO.
But how do we get the answer out?
(And how do you put the initial values in, if you are using
MFHI rd ; rd = HI "move from HI" MFLO rd ; rd = LO "move from LO" MTHI rs ; HI = rs "move to HI" MTLO rs ; LO = rs "move to LO"
The multiplication and division operations take some time to execute,¹ and if you try to read the results too soon, you will stall until the results are available. Therefore, it's best to distract yourself with some other operations while waiting for the multiplication or division operation to do its thing. (For example, you might check if you need to raise a runtime exception because you just asked the processor to divide by zero.)
The temperamental part of the HI and LO registers is in how you read the values out.
Tricky rule number one:
Once you perform a
both of the previous values in
HI and LO are lost.
That means you can't do this:
MULT r1, r2 ; HI:LO = r1 * r2 (signed) ... stuff that doesn't involve HI or LO ... MTHI r3 ; HI = r3 ... stuff that doesn't involve HI or LO ... MFLO r4 ; r4 = GARBAGE
You might naïvely think that the
the value in the HI register and leaves the
LO register alone,
but since this is the first write to either of the
HI or LO registers since the last
multiplication or division operation,
both registers are lost, and your attempt to fetch
the value of LO will return garbage.
Note that this applies only to the first write to HI
The second write behaves as you would expect.
if you perform
MTHI followed by
MTHI will set HI and corrupt LO,
MTLO will set LO and leave
Tricky rule number two:
If you try to read a value from HI or LO,
you must wait two instructions before performing any operation
that writes to
HI or LO.
Otherwise, the reads will produce garbage.
The instruction that writes to
HI or LO
could be a multiplication or division operation, or it could be
Tricky rule number two means that the following sequence is invalid:
DIV r1, r2 ; LO = r1 / r2, HI = r1 % r2 (signed) ... stuff that doesn't involve HI or LO ... MFHI r3 ; r3 =
r1 % r2GARBAGE MULT r4, r5 ; HI:LO = r4 * r5 (signed)
MULT comes too soon after the
MFHI will put garbage
You need to stick two instructions between the
MFHI and the
MULT in order to avoid this.
(Tricky rule number two was removed in the R8000.
On the R8000, if you perform a multiplication or division or
too soon after a
the processor will stall until the danger window has passed.)
Okay, next time we'll look at constants.