SQL Server Function to get the Hour of the Year

This function returns an integer of the hour of the year passed as a variable.

 IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[util].[uf_GetHourOfYear]')

 AND type IN (N'FN', N'IF', N'TF', N'FS', N'FT'))

 DROP FUNCTION [util].[uf_GetHourOfYear]

GO

 CREATE FUNCTION [util].[uf_GetHourOfYear](

  @date DATETIME

 RETURNS INTEGER

 WITH EXECUTE AS CALLER

AS

 /**********************************************************************************************************

 * UDF Name:

 * [util].[uf_GetHourOfYear]

 * Parameters:

 * @date datetime - The date to convert

 * Purpose: This function returns an integer of the hour of the year passed as a variable.

 * Example:

  select [util].[uf_GetHourOfYear](GETDATE())

 * Revision Date/Time:

 * August 1, 2007

 **********************************************************************************************************/

 BEGIN

  -- declare variables

  DECLARE @result integer;

  SET @result = (DATEPART(dy,@DATE) - 1) * 24 + DATEPART(hh,@DATE);

  -- return results.

  RETURN @result;

 END;

GO

 SELECT [util].[uf_GetHourOfYear](GETDATE());

GO

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